Question

Tìm x biết

\(\left(-2\right)^x=4^5.16^2\)

Answer 1

khya r mà đăng à bn

\(\left(-2\right)^x=\left(2^2\right)^2.\left(2^4\right)^2\)

\(\left(-2\right)^x=2^4.2^8=2^{12}\)

\(=>x=12\)

Answer 2

\(\left(-2\right)^x=\left(2^2\right)^5.\left(2^4\right)^2\)

\(\left(-2\right)^x=2^{10}.2^8\)

\(\left(-2\right)^x=2^{18}\)

\(=>x=18\)

Answer 3

(-2)^x = 4⁵.16²

(-2)^x = 2¹⁰ . 2⁸

(-2)^x = 2¹⁸ = (-2)¹⁸

=> x = 18