Question

tìm x biết

\(\frac{x+2}{2012}+\frac{x+3}{2011}+\frac{x+4}{2010}+\frac{x+5}{2009}\)

Answer 1

de thieu

Answer 2

x=-2004

Answer 3

x là -2004 nhỉ 

mk tk nhé

Answer 4

de thieu tong gia tri cua tat ca phan so

Answer 5

Đánh đề sai rồi bạn, phải là :

\(\frac{x+2}{2012}+\frac{x+3}{2011}=\frac{x+4}{2010}+\frac{x+5}{2009}\)

\(\frac{x+2}{2012}+1+\frac{x+3}{2011}+1=\frac{x+4}{2010}+1+\frac{x+5}{2009}+1\)

\(\frac{x+2014}{2012}+\frac{x+2014}{2011}=\frac{x+2014}{2010}+\frac{x+2014}{2009}\)

\(\frac{x+2014}{2012}+\frac{x+2014}{2011}-\frac{x+2014}{2010}-\frac{x+2014}{2009}=0\)

\(\left(x+2014\right)\left(\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}\right)=0\)

mà \(VP\ne0\)

\(\Rightarrow x+2014=0\)

\(\Rightarrow x=-2014\)

Vậy......

Answer 6

Nếu đề bạn là: \(\frac{x+2}{2012}+\frac{x+3}{2011}+\frac{x+4}{2010}+\frac{x+5}{2009}\)

\(\Rightarrow\frac{x+2}{2012}+\frac{x+3}{2011}=\frac{x+4}{2010}-\frac{x+5}{2009}\)

\(\Leftrightarrow\left(\frac{x+2}{2012}+1\right)+\left(\frac{x+3}{2011}+1\right)=\left(\frac{x+4}{2010}+1\right)-\left(\frac{x+5}{2009}+1\right)\)

\(\Leftrightarrow\frac{x+2014}{2012}+\frac{x+2014}{2011}=\frac{x+2014}{2010}-\frac{x+2014}{2009}\)

\(\Leftrightarrow\left(x+2014\right)\left(\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}\right)=0\)

Do \(\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}\ne0\) nên \(x+2014=0\Leftrightarrow x=-2014\)