Question

tìm x, biết:\(\dfrac{x+98}{2}+\dfrac{x+45}{55}+\dfrac{x-1}{101}=\dfrac{x+5}{95}+\dfrac{x+30}{70}+\dfrac{x-3}{103}\)

Answer 1

`(x+98)/2+(x+45)/55+(x-1)/101=(x+5)/95+(x+30)/70+(x-3)/103`

`=>((x+98)/2+1)+((x+45)/55+1)+((x-1)/101+1)=((x+5)/95+1)+((x+30)/70+1)+((x-3)/103+1)`

`=>(x+100)/2+(x+100)/55+(x+100)/101=(x+100)/95+(x+100)/70+(x+100)/103`

`=>(x+100)/2+(x+100)/55+(x+100)/101-(x+100)/95-(x+100)/70-(x+100)/103=0`

`=>(x+100)(1/2+1/55+1/10-1/96-1/70-1/103)=0`

`=>x+100=0`

`=>x=-100` 

Answer 2

\(=\left(\dfrac{x+98}{2}+1\right)+\left(\dfrac{x+45}{55}+1\right)+\left(\dfrac{x-1}{101}+1\right)=\left(\dfrac{x+5}{95}+1\right)+\left(\dfrac{x+30}{70}\right)+\left(\dfrac{x-3}{103}\right)\)

\(=\dfrac{x+100}{2}+\dfrac{x+100}{ }+\dfrac{x+100}{ }\)