1 Tìm x:
( \(3x-2\frac{1}{3}\)):( \(3\frac{1}{4}-5\frac{2}{3}+1\frac{4}{5}\)) = \(2-1\frac{1}{3}x\)
2. Tìm x:
\(\frac{x+\frac{2\left(3-x\right)}{5}}{14}-\frac{5x-4\left(x-1\right)}{24}=\frac{7x+2+\frac{9-3x}{5}}{12}+\frac{2}{3}\)
3. Tìm x:
\(\left(1+3x\right)^2-3x\left(2x+6\right)=\left(4-3x\right)\left(x+3\right)-\left(2x-1\right)^2\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
tìm x , biết
1, 2\(\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)
2, \(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
3, 3\(\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
4, a\(\left(\frac{1}{2}-x\right)-5\left(x-\frac{3}{10}\right)=\frac{7}{4}\)
Tìm x:
a)\(2.\left(3x-\frac{1}{2}\right)-2x=\frac{1}{2}\left(2x-3\right)\)
b)\(\left(2x-\frac{3}{5}\right)^2=\frac{4}{25}\)
c)\(\left(3x-1\right)^3=27\)
d)\(5-\left|x\right|=2\)
e)|2x+1|-3=3
f)|3-2x|=5
\(\left(5-x\right)\left(3x-\frac{1}{4}\right)=0\)
tìm x , biết
1, 2\(\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)
2, \(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
3, 3\(\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
4, a\(\left(\frac{1}{2}-x\right)-5\left(x-\frac{3}{10}\right)=\frac{7}{4}\)
Tìm x, biết:
a, 2x-10-[3x-14-(4-5x)-2x] = 2
b,\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5\)
Tìm x biết:
\(\frac{-1}{2}\times\left(3x-1\right)+\frac{3}{4}\left(3-2x\right)=-3\times\left(\frac{x}{2}-1\right)-\left(\frac{4}{5}\right)^{-1}\)
Tìm x, biết:
a)\(-3\frac{1}{2}+\frac{1}{3}.\left(x-1\right)=-1\frac{1}{3}:2\frac{1}{3}\)
b)\(\frac{x-1}{4}=\frac{x-2}{5}\)
c)\(\frac{x}{0,04}=\frac{0,09}{x}\)
d)\(4:\left(x-1\right)=\left(x-1\right):9\)
e)\(3\frac{1}{2}:x.\frac{1}{2}=5\frac{1}{3}:\frac{1}{2}.\frac{1}{5}\)
f)/2x-3/=5
g)\(\left(2x-\frac{1}{3}\right)^2=\left(1=3x\right)^2\)
h) \(\left(3-\frac{1}{2}:x\right)^2=\frac{1}{4}\)
i) \(\left(3-1\frac{1}{2}:x\right)^3=\frac{1}{8}\)
Tìm x, biết
1, \(-\frac{3}{2}\left(\frac{4}{5}-\frac{2}{3}\right)+x=4\left(x-\frac{2}{3}\right)\)
2, \(2\left(\frac{3}{2}-x\right)-\frac{1}{3}=7x-\frac{1}{4}\)
3, \(\frac{1}{5}\left(\frac{-3}{5}10\right)+5x=x-\frac{2}{3}\)
4, \(-\frac{3}{2}\left(5-\frac{1}{6}\right)+4\left(x-\frac{1}{2}\right)=1\)