Question

Tìm x, biêt

a, \(x+x+2x=164\)

b, \(\frac{1}{2}x:1\frac{12}{7}x=\frac{23}{17}:x\)

c, \(2x+x-x+3x+2x=648\)

Nhanh mình tick

Answer 1

\(a,\)\(x+x+2x=164\)

\(\Rightarrow4x=164\)

\(\Rightarrow x=41\)

Answer 2

a, x+x+2x=164 

    4x=164

     x= 164:4

      x=41

Answer 3

a x + x + 2x = 164

4x = 164

x = 164 : 4 

x = 41

Answer 4

c, \(2x+x-x+3x+2x=648\)

\(\Rightarrow7x=648\)

\(\Rightarrow x=\frac{648}{7}\)

Answer 5

C. \(x+x+2x=164\)

\(x.\left(2+1+1\right)=164\)

\(x.4=164\)

\(x=164:4\)

\(x=41\)