a) \(\left(5x-2\right)\left(5x+2\right)-\left(5x+3\right)\left(5x-4\right)=0\)
\(\Leftrightarrow5x+8=8\)
\(\Leftrightarrow5x=8-8\)
\(\Leftrightarrow x=5.0\)
\(\Leftrightarrow x=0\)
b)
\(\left(4x-3\right)\left(4x+2\right)+\left(4x+5\right)\left(1-4x\right)=2.5^2\)
\(16x^2+8x-12x-6+4x-16x^2+5-20x=50\)
\(-20x-1=50\)
\(-20x=51\)
\(x=\frac{-51}{20}\)
Vậy \(x=\frac{-51}{20}\)