a) 3(x+5)=x-7
<=> 3x+15=x-7
<=> 3x+15-x+7=0
<=> 2x+22=0
<=> 2x=-22
<=> x=-11
b) Ta có 6x+1=2(3x-1)+3
=> 3 chia hết cho 3x-1
=> 3x-1 \(\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)
Ta có bảng
3x-1 | -3 | -1 | 1 | 3 |
x | \(\frac{-2}{3}\) | 0 | \(\frac{2}{3}\) | \(\frac{4}{3}\) |
Mà x nguyên => x=0
a, 3x + 5 = x - 7
<=> 3x -x = -7 -5
<=> 2x = -12
<=> x = -6