\(\left(2x-3\right)^2=16\)
\(\Rightarrow\left(2x-3\right)^2=4^2\)
\(\Rightarrow2x-3=4\)
\(2x=4+3=7\)
\(x=7:2=\frac{7}{2}\)
k mk nha.
#ngố
Mk nghĩ z thui.Sai thui nha!
(2x-3)2=16
=>(2x-3)2=42
=>2x-3=4
=>2x=4+3
=>2x=7
=>x=7:2
=>x=7/2
K mk nha!
Tìm x biết:
(2x-3)2=16
(2x-3)2=42
=>2x-3=4
2x=4+3
2x=7
x=7:2
x=3,5
chuk bn hk tốt :)
\(\left(2x-3\right)^2=4^2\)
\(=>2x-3=4\)
\(=>2x=7\)
\(x=\frac{7}{2}\)
\(\left(2x-3\right)^2=16\)
\(\Rightarrow\left(2x-3\right)^2=4^2\)hoặc \(\left(2x-3\right)^2=\left(-4\right)^2\)
\(2x-3=4\) \(2x-3=-4\)
\(2x=4+3\) \(2x=-4+3\)
\(2x=7\) \(2x=-1\)
\(x=\frac{7}{2}\) \(x=\frac{-1}{2}\)
Vậy \(x=\frac{7}{2}\)hoặc \(x=\frac{-1}{2}\)
