Question

Tìm x, biết

1)x³-5x²+8x-4=0

2)2x³-x²+3x+6=0

Answer 1

1,

<=> \(\left(x-1\right)\left(x-2\right)^2=0\)

=> x=1 hoặc x=2

2, 

<=>\(\left(x+1\right)\left(2x^2-3x+6\right)\)=0

=> x=-1

Answer 2

1.

<=> ( x -1 ) ( x - 2 ) ² = 0

=> x = 1 hoặc x = 2

2.

<=> ( x + 1 ) ( 2x² - 3x + 6 ) = 0

=> x = -1