a) \(x+\frac{3}{2}=\frac{9}{2}\)
\(\Rightarrow x=\frac{9}{2}-\frac{3}{2}=\frac{6}{2}=3\)
b) \(\frac{1}{3}x+\frac{3}{4}x-75\%=-5\frac{1}{4}\)
\(\Leftrightarrow\frac{4x}{12}+\frac{9x}{12}-\frac{9}{12}=-\frac{63}{12}\)
\(\Leftrightarrow\frac{13x-9}{12}=\frac{-63}{12}\)
\(\Rightarrow13x-9=-63\)
\(13x=-54\Rightarrow x=\frac{-54}{13}\)
a) \(x+\frac{3}{2}=\frac{9}{2}\)
\(\Rightarrow x=\frac{9}{2}-\frac{3}{2}\)
\(\Rightarrow x=\frac{6}{2}=3\)
a, x+\(\frac{3}{2}\)=\(\frac{9}{2}\)
x =\(\frac{9}{2}\)-\(\frac{3}{2}\)
x =3
b, \(\frac{1}{3}x\)+\(\frac{3}{4}x\)- 75%=\(\frac{-21}{4}\)
(\(\frac{1}{3}\)+\(\frac{3}{4}\)). x-\(\frac{3}{4}\)=\(\frac{-21}{4}\)
x=\(\frac{-21}{4}\)+\(\frac{3}{4}\)
x=\(\frac{-9}{2}\)
