\(\Rightarrow8x^2-10x+12x-15=0\\ \Rightarrow2x\left(4x-5\right)+3\left(4x-5\right)=0\\ \Rightarrow\left(2x+3\right)\left(4x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x=-3\\4x=5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{5}{4}\end{matrix}\right.\)
