\(x\left(x-5\right)\left(x+5\right)-\left(x-2\right)\left(x^2+2x+4\right)=-17\)
\(\Leftrightarrow x^3-25x-x^3+8=-17\)
\(\Leftrightarrow-25x=-25\)
hay x=1
Tìm x biết: x.(x-5).(x+5)-(x+2).(x^2-2x+4)=17
Tìm X biết : x(x-5)(x+5)-(x+2)(x^2-2x+4)=17
bài 3: tìm x , biết:
a)(x+3).(2x-1)-(x-3).(x+1)=0
b)(x+4).(2x-3)-3.(x-2).(x+2)=0
c)x.(x-5).(x+5)-(x+2).(x2-2x+4)=17
tìm x biết
a) (6x-3) (2x+4) + (4x-1) (5-3x) = -21
b) 6x (3x+5) - 2x (9x-2) + (17-x) (x-1) + x (x-18) =0
c) (15-2x) (4x+1) - (13-4x) (2x-3) - (x-1) (x+2) + x2=52
d) (8x-3) (3x+2) - (4x+7) (x+4) = (2x+1) (5x-1) - 33
Tìm x, biết:
A) (x -1)^3+(2-x)(4+2x+x^2)+3x(x+2)=17
B) (x+2)(x^2-2x+4)-x(x^2-2)=15
C) (5x-2)(5x+2)-(5x+3)(5x-4)=8
D) (4x-3)(4x+2)+(4x+5)(1-4x)=2.5^2
tìm x biết x+6/2+2(x+17)/3+5(x-10)/6 =2x+6
(x+3) (x-2) +3x= 4(x+3/4)
(x^2-5) (x+2)+5x = 2x^2+17
Tìm x giúp mình nha
tìm x
a/ 25x2-2=0
b/ (x+2)(x2-2x+4)+x(5-x)(x+5)=-17
thank trước nha
Tìm x .
x(x-5).(x+5)-(x+2).(x^2-2x+4)=17
Mình cần giải thích cặn kẽ ạ !
Cảm ơn .
