Ta có
x*(x-3)+5*(x-3)=0
=>(x-3)(x+5)=0
=> x-3=0 hoặc x+5=0
=> x=3 hoặc x=-5
Ta có
(x+3)*(x55) là tương tự trên
Ta có
7*(x-3)-4(x-3)=0
=>(7-4)(x-3)=0
=>x=3
KL
tim x biet (x^3+5)(x^3+10)(x^3+15)(x^3+30)<0
Tim x biet : 20 . 2^x + 1 = 10.4^2 + 1
Tim x : ( 4-x:2)^3 - 1 = 2 . (2^3 - 5 : 2^0 )
tim x thuoc z biet
(x-1)(x-3)=-5
(x+1)(x+4)=0
(x^2-4)(x^2-19)<0
tim x biet
a. (x-3)(x+5)=0
b./9-2x/+x+3=2x+15
c./x+1/+/x-1/=4
Tim so nguyen x biet:
a,x-(-24)=3
b,(x+5)-(x-9)=x+3
c,c(x+2)=0
d,(x-1)^2=0
e,x^2-3x=0
f,-13-(6-|x+1|)=24
g,26-|x+9|=-13
i,(3x-6).3=3^4
TIM X , Y BIET
A, I X- 3 I + I Y - 5 I < HOẶC = 0
B , I X- Y + 3 I + I Y - 4 I = 0
tim x biet
(3.x-5)-(2.x-7)=0
tim x biet
(5 - x ) . ( x + 3 ) > 0
Tim so nguyen x biet
5x + 2 - 5x - 1 = 3100
(x - 4)(2x + 3) < 0
