x + 8 = x + 7 + 1
Để x + 8 chia hết cho x + 7 thì 1 chia hết cho x + 7
x + 7 = 1 hoặc x + 7 = -1
*) x + 7 = 1
x = 1 - 7
x = -6
*) x + 7 = -1
x = -1 - 7
x = -8
Vậy x = -8; x = -6
\(\text{x + 8 }⋮\text{ x + 7}\)
\(\Rightarrow\) \(\text{x + 8 = x + 7 + 1}\)
mà \(\text{ x + 7 ⋮ x + 7 + 1}\)
\(\Rightarrow\) \(\text{ 7 }⋮\text{ x + 1}\)
\(\Rightarrow\) \(\text{x + 1 }\in\) \(\text{Ư( 7 )}\)
Có \(\text{Ư( 7 ) }\)\(\text{=}\) \(\left\{1;7\right\}\)
suy ra :
+) \(\text{x + 1 = 1}\) \(\Rightarrow\) \(\text{x = 0}\)
+) \(\text{x + 1 = 7}\) \(\Rightarrow\) \(\text{x = 6}\)