(x-1/3)2=(1/2)2
x-1/3=1/2
x=1/2+1/3=5/6
(x-1/3)2=(1/2)2
x-1/3=1/2
x=1/2+1/3=5/6
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
a)\(\frac{1}{6}x+\frac{1}{10}-\frac{4}{15}x+1=\)\(0\)
b)\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(-\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
c)\(\frac{1}{2}x-\frac{11}{15}:\frac{33}{35}=-\frac{1}{3}\)
Tìm x biết:
!.TÌm x, biết
a) x.(x-2)=0
b) \(\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{4}\right).\left(X-3\right)=0\)
c) (X-10).(X-20)=0
d) (x-2).(x^2-1)=0
e) 2|4-x|=|-8|
tìm x biết :
a. \(\frac{1}{3}.x+\frac{2}{5}.\left(x-1\right)=0\)
b.\(3.\left(2.x-\frac{5}{4}\right)=\left(3-1\frac{1}{2}\right).\left(x-\frac{1}{2}\right)\)
tìm x biết : \(4\left(x-\frac{1}{4}\right)-3\left(x+\frac{2}{3}\right)=0\)
Tìm x, biết:
a)\(\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
b)\(\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)
Bài tập: Tìm x, biết:
a) \(\frac{3}{5}-\frac{4}{3}-x=\frac{-1}{2}\)
b) \(\frac{1}{2}x+\frac{1}{3}x+\frac{1}{6}x=\frac{2}{9}\)
c) \(\left(\frac{1}{3}x+\frac{3}{2}\right)\cdot\left(\frac{3}{2}x-\frac{4}{3}\right)=0\)
( Cần gấp nhé. Mong các bạn giúp mình. )
Tìm x, y lá số tự nhiên khác 0, biết
a) \(\frac{1}{x}-\frac{2}{y}=\frac{1}{4}\)
b)\(\frac{x}{2}+\frac{3}{y}=\frac{4}{7}\)
Tìm x, biết :
a) \(\left(\frac{3}{4}.x-\frac{9}{16}\right).\left(\frac{1}{3}+\frac{-3}{5}:x\right)=0\)
b) \(\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)
c) \(\left(x+\frac{3}{5}\right).\left(x+1\right)< 0\)