\(\left(x-\frac{5}{9}\right)^2=\frac{16}{25}\)
=> \(\left(x-\frac{5}{9}\right)^2=\left(\frac{4}{5}\right)^2\)
=> \(\orbr{\begin{cases}x-\frac{5}{9}=\frac{4}{5}\\x-\frac{5}{9}=-\frac{4}{5}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{61}{45}\\x=-\frac{11}{45}\end{cases}}\)
Vậy \(x\in\left\{\frac{61}{45};-\frac{11}{45}\right\}\)là giá trị cần tìm
( x - 5/9 )2 = 16/25
<=> ( x - 5/9 )2 = ( ±4/5 )2
<=> x - 5/9 = 4/5 hoặc x - 5/9 = -4/5
<=> x = 61/45 hoặc x = -11/45
