(x - 3)4 =16
=> 24 = 16
=> x- 3 = 2
=> x = 5
4(x-3) =16
=> 42 = 16
=> x-3 = 2
=> x = 5
(x - 3)4 = 16
(x - 3)4 = 24 = (-2)4
=> \(\orbr{\begin{cases}x-3=2\\x-3=-2\end{cases}}\)=> \(\orbr{\begin{cases}x=5\\x=1\end{cases}}\)
4x-3 = 16
4x-3 = 42
=> x - 3 = 2
=> x = 2 + 3
=> x = 5
a, \(\left(x-3\right)^4=16\)
\(\Leftrightarrow\left(x-6\right)^4=\left(\pm2\right)^4\)
\(\Leftrightarrow\hept{\begin{cases}x-6=2\\x-6=-2\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=8\\x=4\end{cases}}\)
Vậy \(x\in\left\{4;8\right\}\)
b, \(4^{x-3}=16\)
\(\Leftrightarrow4^{x-3}=4^2\)
\(\Leftrightarrow x-3=2\)
\(\Leftrightarrow x=2+3=5\)
Vậy \(x=5\)