\(\left(x+1\right)+\left(x+2\right)+...+\left(x+2017\right)=0\)
\(\Leftrightarrow\left(x+x+...+x\right)+\left(1+2+...+2017\right)=0\)( có 2017 số x )
\(\Leftrightarrow2017x+\frac{\left(2017+1\right)\times2017}{2}=0\)
\(\Leftrightarrow2017x+2035153=0\)
\(\Leftrightarrow2017x=0-2035153\)
\(\Leftrightarrow2017x=-2035153\)
\(x=\left(-2035153\right)\div2017\)
\(x=-1009\)
Vậy x = -1009
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+2017\right)=0\)
\(\Rightarrow2017x+\left(1+2+...+2017\right)=0\)
\(\Rightarrow2017x+2035153=0\)
\(\Rightarrow2017x=0-2035153\)
\(\Rightarrow2017x=-2035153\)
\(\Rightarrow x=-2035153:2017\)
\(\Rightarrow x=-1009\)
Mk ko chắc lắm!Nhưng bn tk mk nha!
