\(đk:x\ge-2\)
\(\sqrt{x+2}=\frac{5}{7}\Leftrightarrow x+2=\frac{25}{49}\Leftrightarrow x=\frac{25}{49}-2=\frac{-73}{49}\left(n\right)\)
vậy \(x=\frac{-73}{49}\)
\(\sqrt{x+2}=\frac{5}{7}\)
\(\Rightarrow x+2=\frac{25}{49}\)
\(\Rightarrow x=\frac{25}{49}-2\)
\(\Rightarrow x=\frac{-73}{49}\)
Vậy, \(x=\frac{-73}{49}\)
\(\sqrt{x+2}=\frac{5}{7}\)
\(\Rightarrow x+2=\left(\frac{5}{7}\right)^2\)
\(\Rightarrow x+2=\frac{25}{49}\)
\(\Rightarrow x=\frac{25}{49}-2\)
\(\Rightarrow x=\frac{-73}{49}\)
\(\Leftrightarrow\orbr{\begin{cases}x+2=\frac{25}{49}\\x+2=\frac{-25}{49}\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-73}{49}\\x=\frac{-123}{49}\end{cases}}\)Vậy ...........
X+2=(5/7)^2
X+2=25/49
X= 25/9-2
X= -1/24/49
