Số số hạng :
(100-1):1+1=100 (số)
Tách x trong ngoặc :
(100x)+(1+2+3+4+5+6+...+100) = 5750
100x+(100 x ( 100+1 ) :2 ) = 5750
100x+5050=5750
100x=700
x=7
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(x\times100+\left(1+2+3+...+100\right)=5750\)
\(x\times100+5050=5750\)
\(x\times100=5750-5050\)
\(x\times100=700\)
\(x=700\div100\)
\(x=7\)
=> x.100 + ( 1+2+3+...+100) = 5750
x.100 + [(100+1).100:2] = 5750
x.100 + 5050 = 5750
x.100 = 5750 - 5050
x.100 = 700
x = 700 : 100
x = 7
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750
Ta có : ( x + x + x + ...+ x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750
( x . 100 ) + ( 1 + 100 ) . 100 : 2 = 5750
( x . 100 ) + 5050 = 5750
=> x . 100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x = 7
Vậy x = 7
Nếu bn ko biết thì . là nhân đó
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750
x + 1 + x + 2 + x + 3 + ... + x + 100 = 5750
( x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
Vậy x = 7
Ta có:
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750
x + ( 1 + 2 + 3 + ... + 100 ) = 5750
x + 5050 = 5750
x = 5750 - 5050
x = 700
Vậy x = 700
Mk nghĩ vậy!!
100.x+(1+2+3+...+100)=5750
100.x+5050=5750
100.x=5750-5050
100.x=700
x=700/100
x=7
ta có(x+x+x+x+...+x)+(1+2+3+...+100)=5750
100x+[(1+100).100]:2=5750
100x=5750-5050
100x=700
x=70
Vậy x =70 nha
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750
Ta có : ( x + x + x + ...+ x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750
( x . 100 ) + ( 1 + 100 ) . 100 : 2 = 5750
( x . 100 ) + 5050 = 5750
=> x . 100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x = 7
Vậy x = 7
TL:
100x+(1+2+3+.....+100)=5750
100x+5050=5750
100x=700
x=7
vậy......
hc tốt
