Question

Tìm x biết : \(\left(x+2\right)^2-x^2=0\)

Answer 1

\(\left(x+2\right)^2-x^2=0\)

\(\Leftrightarrow\left(x+2-x\right)\left(x+2+x\right)=0\)

\(\Leftrightarrow2\left(2x+2\right)=0\)

\(\Leftrightarrow2x+2=0\Leftrightarrow x=-1\)

Answer 2

(x+2-x)(x+2+x)=0\(\leftrightarrow\)4+x=0 =>x= -4

Answer 3

nham x= -2

Answer 4

(x + 2)² - x² = 0

=> ( x + 2 - x ) ( x + 2 + x ) = 0

=> 2( 2x + 2 ) = 0

=> 4 ( x + 1) = 0

=> x + 1 = 0

=> x = -1.