Question

Tìm x biết \(\left(x-3\right).\left(2x+\frac{1}{3}\right)=0\)

Answer 1

=> x - 3 = 0 hoặc 2x + \(\frac{1}{3}\) = 0

+) x - 3 = 0 => x = 3

+) 2x + \(\frac{1}{3}\)= 0 => 2x = \(\frac{-1}{3}\) => x = -1/3 : 2 = -1/6

Vậy x = 3 hoặc  x = -1/6

Answer 2

\(\left(x-3\right)\cdot\left(2x+\frac{1}{3}\right)=0\)

=> \(x-3=0\) hoặc \(2x+\frac{1}{3}=0\)

=> \(x=3\)  hoặc  \(2x=-\frac{1}{3}\)

=> \(x=3\)  hoặc \(x=-\frac{1}{3}:2=-\frac{1}{6}\)