Ta có:
\(\left(3x-5\right)\left(5-3x\right)+9\left(x+1\right)^2=30\)
\(\Leftrightarrow9\left(x^2+2x+1\right)-\left(3x-5\right)\left(3x-5\right)=30\)
\(\Leftrightarrow9x^2+18x+9-\left(9x^2-30x+25\right)=30\)
\(\Leftrightarrow48x-16=30\)
\(\Leftrightarrow48x=46\Leftrightarrow x=\dfrac{23}{24}\)
Tìm x:
\(1,\left(3x-5\right)^2-\left(3x+1\right)^2=8\)
2,\(2x.\left(8x-3\right)-\left(4x-3\right)^2=27\)
3,\(\left(2x-3\right)^2-\left(2x+1\right)^2=3\)
4, \(\left(x+5\right)^2-x^2=45\)
5, \(\left(x-3\right)^3-\left(x-3\right).\left(x^2+3x+9\right)+9.\left(x+1\right)^2=18\)
6,\(x.\left(x-4\right).\left(x+4\right)-\left(x-5\right).\left(x^2+5x+25\right)=13\)
1) \(27+\left(x-3\right).\left(x^2+3x+9\right)=-x\)
2) \(-4\left(x+2\right)-7\left(2x-1\right)+9\left(4-3x\right)=30\)
3) \(x^2-4x+4=0\)
4) \(\left(x-1\right).\left(x^2+x+1\right)-x.\left(x+2\right).\left(x-2\right)=5\)
Tìm x giúp mk vs nha mai mk đi hk rùi
Tìm x:
a/ \(\left(6x-2\right)^2+\left(5x-2\right)^2-4\left(3x-1\right)\left(5x-2\right)=0\)
b/ \(\left(x-1\right)\left(x^2+x+1\right)-x\left(x+2\right)\left(x-2\right)=5\)
c/ \(\left(x-1\right)^3-\left(x+3\right)\left(x^2-3x+9\right)+3\left(x^2-4\right)=2\)
* Tìm x :
a, \(\left(3x-2\right)^2-\left(3x-5\right).\left(3x+2\right)=11\)
b, \(\left(4x-3\right)^2-\left(4x-5\right).\left(4x+5\right)=32\)
c, \(\left(5x-2\right)^2-\left(5x+3\right).\left(5x-5\right)=1\)
d, \(\left(x-4\right)^2-\left(x-7\right).\left(2x-3\right)=5-x^2\)
Chứng minh biểu thức không phụ thuộc x :
1, \(\left(3x-1\right)^2-2\cdot\left(2x-3\right)\cdot\left(2x+3\right)-\left(x-3\right)^2\)
2, \(\left(3x+2\right)^3-\left(3x-2\right)^3-3\cdot\left(6x-1\right)\cdot\left(6x+1\right)\)
3, \(\left(3x-5\right)^2+3\cdot\left(x+1\right)\cdot\left(x-1\right)-\left(4x-3\right)^2+\left(2x+2\right)\cdot\left(2x+1\right)\)
CM biểu thức sau không phụ thuộc vào giá trị của biến:
\(A=\left(3x-5\right)\left(2x+11\right)-\left(2x+3\right)\left(3x+7\right)\)
\(B=x^3-y^3-\left(x^2+xy+y^2\right)\left(x-y\right)\)
\(C=3x\left(x+5\right)-\left(3x+18\right)\left(x-1\right)+8\)
1) Tìm x biết,
\(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=11\)
2) Rút gọn các biểu thức
a) \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
b) \(\left(a-b+c\right)^2-\left(b-c\right)^2+2ab-2ac\)
c) \(\left(3x+1\right)^2-2\left(3x+1\right)\left(3x+5\right)+\left(3x+5\right)^2\)
d) \(\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)
e) \(\left(a+b-c\right)^2+\left(a-b+c\right)^2-2\left(b-c\right)^2\)
3) Chứng minh rằng các biểu thức sau luôn luôn có giá trị dương với mọi giá trị của biến
a) \(9x^2-6x+2\)
b) \(x^2+x+1\)
c) \(2x^2+2x+1\)
4) Tìm GTNN của các biểu thức
a) A=\(x^2-3x+5\)
b) B=\(\left(2x-1\right)^2+\left(x+2\right)^2\)
GIÚP MK VỚI!!!!!!!!!!
tìm x:
a) \(\left(x-3\right)\left(x^2+3x+9\right)-x\left(x-4\right)\left(x+4\right)=5\)
b) \(\left(x-2\right)^3-\left(x+5\right)\left(x^2-5x+25\right)+6x^2=11\)
1. làm tính nhân
a,\(2x.\left(x^2-7x-3\right)\)
b,\(\left(-2x^3+\dfrac{3}{4}y^2-7xy\right).4xy^2\)
c,\(\left(-5x^3\right).\left(2x^2+3x-5\right)\)
d,\(\left(2x^2-\dfrac{1}{3}xy+y^2\right).\left(-3x^3\right)\)
e,\(\left(x^2-2x+3\right).\left(x-4\right)\)
f,\(\left(2x^3-3x-1\right).\left(5x+2\right)\)
2.tính nhanh
a,\(892^2+892.216+108^2\)
b,\(36^2+26^2-52.36\)
3.tìm x biết
a,\(7x^2-28=0\)
b,\(\dfrac{2}{3}x.\left(x^2-4\right)=0\)
c,\(2x.\left(3x-5\right)-\left(5-3x\right)=0\)
d,\(\left(2x-1\right)^2-25=0\)
4.rút gọn và tính gái trị biểu thức
M=\(\left(x+3\right)\left(x^2-3x+9\right)-\left(x^3+54-x\right)\)
với x=27
