\(\left|2x-3\right|-x=\left|2-x\right|\)
TH1: \(\dfrac{3}{2}\le x\le2\)
\(\Rightarrow\left(2x-3\right)-x=2-x\)
\(\Leftrightarrow x-3=2-x\)
\(\Leftrightarrow2x=5\)
\(\Leftrightarrow x=\dfrac{5}{2}\left(ktm\right)\)
TH2: \(x>2\)
\(\Rightarrow\left(2x-3\right)-x=x-2\)
\(\Leftrightarrow x-3=x-2\)
\(\Leftrightarrow0=1\) (vô lý)
TH3: \(x< \dfrac{3}{2}\)
\(\Rightarrow\left(3-2x\right)-x=2-x\)
\(\Leftrightarrow3-3x=2-x\)
\(\Leftrightarrow3-2=-x+3x\)
\(\Leftrightarrow x=\dfrac{1}{2}\left(tm\right)\)
Vậy: ....