a: ĐKXĐ: \(x\in R\)
\(\sqrt{\left(x+3\right)^2}=12\)
=>\(\left|x+3\right|=12\)
=>\(\left[{}\begin{matrix}x+3=12\\x+3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=-15\end{matrix}\right.\)
b: ĐKXĐ: x>=1
\(\sqrt{25x-25}-\sqrt{9x-9}=10\)
=>\(5\sqrt{x-1}-3\sqrt{x-1}=10\)
=>\(2\sqrt{x-1}=10\)
=>x-1=25
=>x=26(nhận)
giải phương trình
a)\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
b)\(\sqrt{16x+16}-\sqrt{9x+9}+\sqrt{4x+4}+\sqrt{x+1}=16\)
c)\(\sqrt{4x+20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x+45}=4\)
d)\(\dfrac{1}{3}\sqrt{2x}-\sqrt{8x}+\sqrt{18x}-10=2\)
tìm x biết
a)\(\frac{3\sqrt{x}-5}{2}-\frac{2\sqrt{x}-7}{3}+1=\sqrt{x}\)
b)\(\sqrt{9x^2+45}-\frac{1}{12}\sqrt{16x^2+80}+3\sqrt{\frac{x^2+5}{16}}-\frac{1}{4}\sqrt{\frac{25x^2+125}{9}}=9\)
Tìm x, biết
a) \(\sqrt{9x^2}\)=12
b) \(\sqrt{25x^2}\)=\(\left|-50\right|\)
Tìm x, biết:
a, \(\sqrt{4x+20}-3\sqrt{5+x}+\frac{4}{3}\sqrt{9x+45}=6\)
b, \(\sqrt{25x-25}-\frac{15}{2}\sqrt{\frac{x-1}{9}}=6+\sqrt{x-1}\)
4. giái phương trình
a.\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
b.\(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}\sqrt{9x-9}+24\sqrt{\dfrac{x-1}{64}}=-17_{ }\)
Tìm x, biết:
a)\(\sqrt{4-5x}=12\)
b)\(\sqrt{x^2-14x+49}\)\(-3x=1\)
c)\(\sqrt{9x-9}\)+\(2\sqrt{16x-16}\)\(-\frac{1}{3}\sqrt{25x-25}\)\(=\sqrt{x-1}\)
a \(\sqrt{4x-20}+\sqrt{x-5}-\dfrac{1}{3}\sqrt{9x-45}=4\)
b \(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}=4\)
c \(\dfrac{1}{3}\sqrt{x-2}-\dfrac{2}{3}\sqrt{9x-18}+6\sqrt{\dfrac{x-2}{81}=-4}\)
d \(\sqrt{9x+27}+4\sqrt{x+3}-\dfrac{3}{4}\sqrt{16x+48}=0\)
a) \(\sqrt{4x^2-9}=2\sqrt{x+3}\)
b) \(\sqrt{4x+20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
c) \(\dfrac{2}{3}\sqrt{9x-9}-\dfrac{1}{4}\sqrt{16x-16}+27\sqrt{\dfrac{x-1}{81}}=4\)
d)\(5\sqrt{\dfrac{9x-27}{25}}-7\sqrt{\dfrac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\dfrac{9x^2-81}{81}}=0\)
\(\frac{1}{4}\sqrt{\frac{25x^2+125}{9}}\)Tìm x biết
a) \(\frac{3\sqrt{x}-5}{2}\)- \(\frac{2\sqrt{x}-7}{3}\)+1=20
b) \(\sqrt{9x^2+45}\) - \(\frac{1}{12}\sqrt{16x^2+80}\) +\(3\sqrt{\frac{x^2+5}{16}}\)
-\(\frac{1}{4}\sqrt{\frac{25x^2+125}{9}}\)=9
