\(a,\frac{x+5}{2010}+\frac{x+6}{2009}+\frac{x+7}{2008}=-3\)
\(\Rightarrow\left(\frac{x+5}{2010}+1\right)+\left(\frac{x+6}{2009}+1\right)+\left(\frac{x+7}{2008}+1\right)=0\)
\(\Rightarrow\frac{x+2016}{2010}+\frac{x+2016}{2009}+\frac{x+2006}{2008}=0\)
chỉ bt lm v thoi "(
a) \(\frac{x+5}{2010}+\frac{x+6}{2009}+\frac{x+7}{2008}=-3\)
<=> \(\frac{x+5}{2010}+1+\frac{x+6}{2009}+1+\frac{x+7}{2008}+1=0\)
<=> \(\frac{x+2015}{2010}+\frac{x+2015}{2009}+\frac{x+2015}{2008}=0\)
<=> \(\left(x+2015\right)\left(\frac{1}{2010}+\frac{1}{2009}+\frac{1}{2008}\right)=0\)
<=> \(x+2015=0\) (do 1/2010 + 1/2009 + 1/2008 # 0 )
<=> \(x=-2015\)
Vậy...
b) mạo phép chỉnh đề
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+344}{5}=0\)
<=> \(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+344}{5}-3=0\)
<=> \(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{5}=0\)
làm tương tự a
Cách là của Umi đúng rồi nhưng khi tính thì sai nha.
Mình làm tiếp từ dòng 2
\(\frac{x+2015}{2010}\)+ \(\frac{x+2015}{2009}\)+ \(\frac{x+2015}{2008}\)= 0
=> ( x + 2015 ) \(\left(\frac{1}{2010}+\frac{1}{2009}+\frac{1}{2008}\right)\)= 0
=> x + 2015 = 0
Vậy x = - 2015
\(\frac{x+5}{2010}+\frac{x+6}{2009}+\frac{x+7}{2008}=-3\)
\(\Leftrightarrow\left(\frac{x+5}{2010}+1\right)+\left(\frac{x+6}{2009}+1\right)+\left(\frac{x+7}{2008}+1\right)=0\)
\(\Leftrightarrow\frac{x+2015}{2010}+\frac{x+2015}{2009}+\frac{x+2015}{2008}=0\)
\(\Leftrightarrow\left(x+2015\right)\left(\frac{1}{2010}\right)+\left(x+2015\right)\left(\frac{1}{2009}\right)+\left(x+2015\right)\left(\frac{1}{2008}\right)=0\)
\(\Leftrightarrow\left(x+2015\right)\left(\frac{1}{2010}+\frac{1}{2009}+\frac{1}{2008}\right)=0\)
Mà \(\frac{1}{2010}+\frac{1}{2009}+\frac{1}{2008}\ne0\) Do đó \(\left(x+2015\right)=0\Leftrightarrow x=-2015\)
b) Sai đề
