Question

tìm x biết :  8x (x-2015)-x+2015=0

 

Answer 1

Ta có: \(8x\left(x-2015\right)-x+2015=0\)

\(\Rightarrow8x\left(x-2015\right)-\left(x-2015\right)=0\)

\(\Rightarrow\left(8x-1\right)\left(x-2015\right)=0\)

\(\Rightarrow\orbr{\begin{cases}8x-1=0\\x-2015=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{8}\\x=2015\end{cases}}}\)

Vậy \(x=\left\{\frac{1}{8};2015\right\}\)

Answer 2

       8x(x - 2015) - (x - 2015) = 0

<=> (8x - 1)(x - 2015) = 0

<=> ...........  đến đây thì dễ rồi :)))) 

Answer 3

8x(x-2015)-x+2015=0

8x(x-2015)-(x-2015)=0

(8x-1)(x-2015)=0

\(\orbr{\begin{cases}8x-1=0\\x-2015=0\end{cases}}\)=>\(\orbr{\begin{cases}8x=-1\\x=2015\end{cases}}\)=>\(\orbr{\begin{cases}x=\frac{1}{8}\\x=2015\end{cases}}\)

vậy x \(\in\){\(\frac{1}{8}\);2015}