Question

Tìm x biết: 56-(2x-1) mũ 2=|3^2-7^2| 🥺

Answer 1

56-(2x-1)^2=|9-49|

<=>56-(2x-1)^2=40

<=>(2x-1)^2=16

<=>2x-1=4

<=>x=5/2

Answer 2

Giải:

56-(2x-1)²=|3²-7²|

56-(2x-1)²=40

      (2x-1)²=56-40

      (2x-1)²=16

⇒(2x-1)²=4² hoặc (2x-1)²=(-4)²

    2x-1=4 hoặc 2x-1=-4

         x=5/2 hoặc x=-3/2

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Answer 3

56-(2x-1)^2=|3^2-7^2|

56-(2x-1)^2=40

(2x-1)^2=56-40

(2x-1)^2=16

(2x-1)^2=4^2

⇒2x-1=4

2x=4+1

2x=5

x=5:2

x=5/2

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Answer 4

\(56-\left(2x-1\right)^2=\left|3^2-7^2\right|\)

\(56-\left(2x-1\right)^2=\left|9-49\right|\)

\(56-\left(2x-1\right)^2=40\)

\(\left(2x-1\right)^2=56-40\)

\(\left(2x-1\right)^2=16\)

\(\left(2x-1\right)=4^2\)

⇒\(2x-1\in\left\{4;-4\right\}\)

TH1:\(2x-1=4\)

\(x=\left(4+1\right):2\)

\(x=2,5=\dfrac{5}{2}\)

TH2:\(2x-1=-4\)

\(x=\left(-4+1\right):2\)

\(x=-1,5=\dfrac{-3}{2}\)