Ta có 3^(x+2) +4.3^(x+1) +3^(x-1) =6^6
=> 3^x . 3^2 + 4.3^x.3+ 3^x.1/3 = 46656
=> 3^x( 9+12+1/3) =46656
=> 3^x .64/3 =46656
=> 3^x =2187
=>3^x = 3^7
=> x=7
Vậy x=7
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\(3^{x+2}+4.3^{x+1}+3^{x-1}=6^6\)
\(\Rightarrow3^{x-1}\left(3^3+4.3^2+1\right)=3^6.2^6\)
\(\Rightarrow3^{x-1}.64=3^6.64\)
\(\Rightarrow3^{x-1}=3^6\)
\(\Rightarrow x-1=6\Leftrightarrow x=7\)
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