\(\left[\left(\frac{3}{4}\right)^3\right]^2=\left(\frac{3}{4}\right)^6=\left(\frac{16}{9}\right)^x=\left[\left(\frac{4}{3}\right)^2\right]^x=\left(\frac{4}{3}\right)^{2x}=\left(\frac{3}{4}\right)^{-2x}\)
=>-2x=6=>x=-3
Tim x biet ( x-3)^4 = 16
4^(x-3) = 16
Tim x,y,z biet:2(x-1)-3(2x+2)-4(2x+3)=16
Tim x biet:
a.2|2x-3|=1/2
b.(x-1)^2=9/16
c.3/5(x-5/6)-1/2(3/2-1)=-1/4
d.1/3+1/6+1/10+......+2/x(x+1)=2015/2016
Tim x biet
1/1*3+1/3*5+1/5*7+1/7*9+...+1/x(x+2)=16/34
Tim x,y,z biet:2(x-1)-3(2x+2)-4(2x+3)=16
giai day du
Tim x biet
1/1*3+1/3*5+1/5*7+1/7*9+...+1/x(x+2)=16/34
1)tim x biet rang:
a)3^x-1=1/243
b)2^x+2^x+3=144
c)81^-2x.27x=9^5
2)tim tiep so ghang thu 5 cua day so sau:-1/a^2;2/a^3;-6/a^4;24/a^5;...
3)tim so tu nhien x biet :
a)4^x+4^x+3=4160
b)2^x-1+5.2^x-2=7/32
Tim x biet 4/15 +1/6-5/9 > 2/3-x-3/4
Ai dung 5 sao lun
tim x thuoc Z biet:
|x-5|+x+3=16
||x+5|-4|=3
Cach lam nua nhe
