Question

tìm x biết 2^x+2*3^x+1*5^x=10800

Answer 1

<=> 2^x+2*3^x+1*5^x-10800=0

=>x=\(\frac{7079}{1250}\)

Answer 2

\(2^{x+2}.3^{x+1}.5^x=10800\)

\(2^x.2^2.3^x.2.5^x=10800\)

\(\left(2.3.5\right)^x.12=10800\)

\(30^x=10800:12\)

\(30^x=900\)

\(30^x=30^2\Rightarrow x=2\)

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Answer 3

2^x+2.3^x+1.5^x=10800

=>2^x.2².3^x.3.5^x=10800

=>2^x.3^x.5^x=10800:3:2²

=>30^x=900

=>30^x=30²

=>x=2

Answer 4

\(2^{x+2}.3^{x+1}.5^x=10800\)

\(\Rightarrow2^x.2^2.3^1.3^x.5^x=10800\) 

 \(\left(2^x.3^x.5^x\right).\left(2^2.3^1\right)=10800\)

       \(\left(2.3.5\right)^x.\left(4.3\right)=10800\)

                     \(30^x.12=10800\)

                      \(30^x=10800:12\)

                      \(30^x=900\)

                      \(^{30^x=30^2\Rightarrow x=2}\)

Answer 5

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Answer 6

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Answer 7

\(2^{x+2}\)\(.3^{x+1}\)\(.5^x\)\(=10800\)

\(\Rightarrow2^x.2^2.3^x.3.5^x=10800\)

\(\Rightarrow\left(2.3.5\right)^x.2^2.3=10800\)

\(\Rightarrow30^x.12=10800\)

\(\Rightarrow30^x=10800:12=900\)

\(\Rightarrow30^x=30^2\)

\(\Rightarrow x=2\)