Vì: |2\(x\) - 1| = |1 - 2\(x\)|
Nên: |2\(x\) - 1| + |1 - 2\(x\)| = 8
⇒ |2\(x\) - 1| + |2\(x\) - 1| = 8
2.|2\(x\) - 1| = 8
|2\(x\) - 1| = 8:2
|2\(x\) - 1| = 4
\(\left[{}\begin{matrix}2x-1=-4\\2x-1=4\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-4+1\\2x=4+1\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-3\\2x=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\)
Vậy \(x\) \(\in\){- \(\dfrac{3}{2}\); \(\dfrac{5}{2}\)}
Tìm x biết
| 2x+3 | + | 2x-1 | = 8/[ 3× (x+1)^2 + 2 ]
Tìm x biết : a) 2x+3/15 = 7/5. b) x-2/9 = 8/3. c) -8/x = -x/18 d) 2x+3/6 = x-2/5. e) x+1/22 = 6/x f) 2x-1/2 = 5/x g) 2x-1/21 = 3/2x+1 h) 10x+5/6 = 5/x+1
Tìm x biết
2x-1/2 = 8/2x-1
Nhanh nhá
Tìm x, biết:
1) |2x-1| = -19- x
8) | 2x-1| =x
9) | 2x+3|= 3x
10) | x+2| = 2x
tìm x biết
a)(x+5^3)=-64
b)(2x-3^2)=9
C)(1\2)^2x-1=1\8
1,tìm x biết:\(\left|2x+3\right|+\left|2x-1\right|=\dfrac{8}{3.\left(x+1\right)^2+2}\)
Tìm x biết:
a) 11/15 - (7/9 + x) × 3/8 = 61/90 + x/3
b) (4x + 1)(-2x + 1/3) = 0
c) 5x(2x - 1/2) + 2(2x - 1/2) = 0
tìm x biết
a,2x-5=3+2x-7x
c,(2x-1)^2 )=(2x-1)^5
b,1/5×-3y=4-3y
d,3×(2x+5)-4×(x-7)=8×(2-3x)
Tìm x biết :
a) ( 2x - 3 ).( x +1 ) > 0
b) ( x + 5 ).(x-7) < 0
c) | 2x - 3 | + 8 = 10
d) ( 2x + 5 ) . | x -8 | . ( x2 + 1 ) = 0
