Question

Tìm x biết (2^x+1-8).(5²-5x)=0

Answer 1

Ta có:(2^x+1-8).(5²-5x)=0

=>2^x+1-8=0;5²-5x=0

=>2^x+1=8;25-5x=0

=>2^x+1=2³;5x=25

=>x+1=3;x=5

=>x=2,5

Vậy x=2,5

Answer 2

=>2^x+1-8=0       5²-5x=0

với 2^x+1-8=0

=>2^x+1=8

=>2^x+1=2³

=>x=2

với 5²-5x=0

=>5x=5²

^=>x=5

 

 

Answer 3

Ta có:(2^x+1-8).(5²-5x)=0

=> 2^x+1-8=0 ; 5²-5x=0

=> 2^x+1=8 ; 25-5x=0

=> 2^x+1=2³ ; 5x=25

=> x+1=3 ; x=5

=>    x=2;5

   Vậy x=2;5