Question

Tìm x, biết: 

(2x - 1)⁶ = (1 - 2x)⁸

Answer 1

\(\left(2x-1\right)^6=\left(1-2x\right)^8\)

<=>\(\left(1-2x\right)^6=\left(1-2x\right)^8\)

<=>\(\left(1-2x\right)^8-\left(1-2x\right)^6=0\)

<=>\(\left(1-2x\right)^6\left(\left(1-2x\right)^2-1\right)=0\)

<=>1-2x=0 hoặc (1-2x)^2-1=0

<=>x=1/2 hoặc x=1

Answer 2

=>(2x-1)⁶-(1-2x)⁸=0

=>(2x-1)⁶-(2x-1)⁸=0

=>(2x-1)⁶.[1-(2x-1)²]=0

=> (2x-1)⁶=0 hoặc 1-(2x-1)²=0

*(2x-1)⁶=0=> 2x=1=>x=1/2

*-(2x-1)²=0=>(2x-1)²=1=1²=-1²

        => 2x-1=1 hoặc 2x-1=-1

        2x-1=1=>x=1

         2x-1=-1=>x=0

 vậy x=0;1;1/2

Answer 3

Nguyễn Quốc Khánh thiếu x=0