tim x biet 1/1.2.3+1/2.3.4+...+1/8.9.10.x=22/45
giup dum minh like cho
Tim x biet:(1/1.2.3+1/2.3.4+...+1/8.9.10)x=22/45
tim x biet (1/(1.2.3)+1/(2.3.4)+1/(3.4.5)+...+1/(8.9.10)).x=22/45
Cho
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right).x=\frac{22}{45}\)
tìm x
Tìm x biết \(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{8.9.10}\right).x=\frac{22}{45}\)
Tìm x biết (\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+....+\frac{1}{8.9.10}.x=\frac{22}{45}\)
Trả lời x=....
Tìm x biết .
Trả lời: x=
Tìm x biết \(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+....+\frac{1}{8.9.10}\right).x=\frac{22}{45}\) .
Trả lời:x =
Kèm theo cách làm
Tìm x :
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right)\) . \(x\) = \(\frac{22}{45}\)
Thanks truoc