Question

tìm x biết (1 phần 2 - 2 phần 5)+(-1 1 phần 3 - 5 phần 6)-(-x+1 phần 10)= 3 phần 10

Answer 1

\(\left(\dfrac{1}{2}-\dfrac{2}{5}\right)+\left(-1\dfrac{1}{3}-\dfrac{5}{6}\right)-\left(-x+\dfrac{1}{10}\right)=\dfrac{3}{10}\)

\(\left(\dfrac{5}{10}-\dfrac{4}{10}\right)+\left(\dfrac{-2}{3}-\dfrac{5}{6}\right)+x-\dfrac{1}{10}=\dfrac{3}{10}\)

\(\dfrac{1}{10}+\left(\dfrac{-4}{6}-\dfrac{5}{6}\right)+x=\dfrac{3}{10}+\dfrac{1}{10}\)

\(\dfrac{1}{10}+\dfrac{-3}{2}+x=\dfrac{4}{10}\)

\(\dfrac{-3}{2}+x=\dfrac{4}{10}-\dfrac{1}{10}\)

\(\dfrac{-3}{2}+x=\dfrac{3}{10}\)

\(x=\dfrac{3}{10}-\dfrac{-3}{2}\)

\(x=\dfrac{3}{10}-\dfrac{-15}{10}\)

\(x=\dfrac{18}{10}=\dfrac{9}{5}\)