Question

tìm x : a (1/2+2x)(2x -3)=0

           b 1/4 -(2x +1/2)^2 =0

Answer 1

a)

`(1/2+2x)(2x-3)=0`

\(=>\left[{}\begin{matrix}\dfrac{1}{2}+2x=0\\2x-3=0\end{matrix}\right.\\ =>\left[{}\begin{matrix}2x=-\dfrac{1}{2}\\2x=3\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=\dfrac{3}{2}\end{matrix}\right.\)

b)

`1/4-(2x+1/2)^2=0`

`=>(2x+1/2)^2=1/4`

\(=>\left[{}\begin{matrix}2x+\dfrac{1}{2}=\dfrac{1}{2}\\2x+\dfrac{1}{2}=-\dfrac{1}{2}\end{matrix}\right.\\ =>\left[{}\begin{matrix}2x=0\\2x=-1\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\)