Question

Tìm x: 4x^2 - 4x + 1 = 0

Answer 1

\(=>4xx-4x+1=0\)

\(4x\left(x-1\right)+1=0\)

\(=>\left[{}\begin{matrix}4x=0\\\left(x-1\right)+1=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x-1=-1\end{matrix}\right.\left[{}\begin{matrix}x=0\\x=0\end{matrix}\right.\)

vậy x=0

Answer 2

\(4x^2-4x+1=0\Leftrightarrow\left(2x-1\right)^2=0\Leftrightarrow x=\dfrac{1}{2}\)