3x - 6 = x2 - 16
<=> x2 - 3x - 10 = 0
<=> x2 - 5x + 2x - 10 = 0
<=> x(x - 5) + 2(x - 5) = 0
<=> (x + 2)(x - 5) = 0
<=> \(\left[{}\begin{matrix}x+2=0\\x-5=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=-2\\x=5\end{matrix}\right.\)
Bài 2: Tìm x, biết: a) (x+2)(x² -2x+4)-x(x²+2)=15 b) (x-2)³-(x-4)(x² + 4x+16) + 6(x+1)=49 c) (x - 1)³ + (2 - x)(4 + 2x + x²)+ 3x(x + 2) = 16 d) (x - 3)³ - (x - 3)(x² + 3x + 9) + 9(x + 1)² = 15
Tìm x biết:
1,
a,3x(x+1) - 2x(x+2) = -x-1
b,2x(x-2020) - x+2020 = 0
c,(x-4)2 - 36 = 0
d,x2 + 8x - 16 = 0
e,x(x+6) - 7x - 42 = 0
f,25x2 - 16 = 0
2,
a,3x3 - 12x = 0
b,x2 + 3x - 10 = 0
Tìm x để x nhận giá trị nguyên
a, 2/x-1
B,-6/3x-2
c,X^4-16/x^4-4x^3+8x^2-16x+16
d,3x^3-7x^2+11x+11/3x-1
e,2x^3+x^2+2x+2/2x+1
bài 1 tìm x
a) 4(18-5x)-12(3x-16)=15(2x-16)-6(x+14)
b) (x+3)(x+2)-(x-2)(x+5)=6
c) -x(x+3)+2=(4x+1)(x-1)+2x
d) (2x+3)(x-3)-(x-3)(x+1) = (2-x)(3x+1)+3
cần gấp mọi người giúp mình với
bài 1: Tìm x nè:
1) (x - 4)x - (x - 3)^ = 0
2) 3x - 6 = x^ - 16
Bài 2 : Tìm x , biết
a) ( 3x -1 ) (2x+7) - ( x +1) (6x-5 ) = 16
b) ( 10x +9 )x - ( 5x -1 ) (2x+3 )= 8
c) ( 3x - 5 ) ( 7- 5x ) + ( 5x +2 )( 3x-2 ) -2 = 0
d) x(x + 1) ( x+6 ) - x3 = 5x
ai giúp e với
tìm x :
3x ( x + 1 ) - 2x ( x + 2 ) = - 1 - x
4x ( x - 2019 ) - x + 2019 = 0
( x - 4 )^2 - 36 = 0
x^2 + 8x + 16 = 0
x ( x + 6 ) - 7x - 42 = 0
25x^2 - 9 = 0
Bài 1: Tìm x :
a. ( x + 4 )2 - ( x + 1 ) ( x - 1 ) = 16
b. ( 2x - 1 )2 + ( x + 3 )2 - 5 ( x + 7 ) ( x - 7 ) = 0
c. ( x - 2 )3 - ( x - 3 ) ( x2 + 3x + 9 ) + 6 ( x + 1 )2 = 49
Bài 1: Tìm x :
a. ( x + 4 )2 - ( x + 1 ) ( x - 1 ) = 16
b. ( 2x - 1 )2 + ( x + 3 )2 - 5 ( x + 7 ) ( x - 7 ) = 0
c. ( x - 2 )3 - ( x - 3 ) ( x2 + 3x + 9 ) + 6 ( x + 1 )2 = 49
