Lời giải:
$(3x-4)(x+3)-(3+1)=12$
$\Leftrightarrow 3x^2+5x-12-4=12$
$\Leftrightarrow 3x^2+5x-28=0$
$\Leftrightarrow (3x-7)(x+4)=0$
$\Leftrightarrow 3x-7=0$ hoặc $x+4=0$
$\Leftrightarrow x=\frac{7}{3}$ hoặc $x=-4$
Tim x, bt:
a) 4.(18- 5x) - 12.( 3x-7) =15.(2x-16) - 6.(x+14)
b) 5.(3x+5) - 4.(2x-3) =5x + 3x(2x-12) +1
1/ \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
2/ \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
3/ \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
4/ \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
5/ \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
tim x biet
a/(3x-5)(2x-1)-(x+2)(6x-1)=0
b/ (3x-5)(3x+2)-(3x-1)2=-5
c/(3x+2)(x-5)=3(x-1)2-2
d/ (x+1)2/3 - (x-2)2/2 = 2x+1/2 (x-3)2/6
g/49x2=(3x+2)2
h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)=0
i/ (x-2)(x2-2x+4)-x(x2+2)=15
k/ 6x2-7x-3=0
m/(x+5)(x-3)+x2-25=0
e/ x3+3x2=4x+12
f/ (6x+7)2(3x+4)(x+1)=6
Tim x: (3x+2)* ( x-1) - 3*(x+1)*(x-2)=4
tim x:
(x-1)(x+2)-x^2+3=5
(x-2)(3x+4)=3x(x-2)
5(x-3)+(x-2)(5x-1)=5x^2
tim x biet:
x+x2-x3-x4=0
2x3+3x2+2x2+3=0
x2-x-12=0
tim x biet;(2x-1)(3x+1)+(3x-4)(3-2x)=5
Bai 1: Tim x
a) 13x^2-15x-2=0
b)x^4-4x^2+3=0
c) (5x-2)^2+29x-(3x+1)^2=-11x
d) 4(x-2)^2-27(x-2)-7=0
Bai 2: Phan tich da thuc thanh nhan tu
a) 9x^2-25y^2+10y-1
b) (x-2)(x+2)(x^2-10)-72
c) x^3+y(1-3x^2)+x(3y^2-1)-y^3
d) 2x^2-5xy+2y^2
e) x^3-5x^2+3x+9
g) (x^2+3x+2)(x^2+7x+12)+1
h) x^8+x^7+1
giải các phương trình sau
1, \(\dfrac{3}{x-3}+\dfrac{4}{x+3}=\dfrac{3x-7}{x^2-9}\)
2, \(\dfrac{3}{x-4}-\dfrac{4}{x+4}=\dfrac{3x-4}{x^2-16}\)
3, \(\dfrac{5x^2-12}{x^2-1}+\dfrac{3}{x-1}=\dfrac{5x}{x+1}\)
tim x
a, 4x ( x-5 ) -x (4x-7) = 12
b, ( 2-3x) x +6x ( x-7 ) =4
bạn nào làm nhanh nhất được 3 like nhé
