Question

tìm x: (3x-1)^2-16=0. m.n giúp mk vs nha:)))

Answer 1

       (3x - 1 )² - 16 =0

<=>(3x - 1 )² = 16

<=>3x-1  =4

<=>x=5/3

Answer 2

(3x - 1)² - 16 = 0

<=> (3x - 1)² - 4² = 0

<=> (3x - 1 - 4)(3x - 1 + 4) = 0

<=> (3x - 5)(3x + 3)  = 0

<=> 3x - 5 = 0 hoặc 3x + 3 = 0

<=> x = 5/3 hoặc x = - 1

Answer 3

(3x-1)^2-16=0

(3x-1)^2=16  

Th1: 3x-1=4

        3x=5  

        x=5/3

Th2: 3x-1=-4    

        3x=-3            

          x=-1