Question

tìm x 
(2x+1/3)^2-1/2=1 3/4

Answer 1

\(\left(2x+\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\\ \Rightarrow\left(2x+\dfrac{1}{3}\right)^2-\dfrac{1}{2}=\dfrac{7}{4}\\ \Rightarrow\left(2x+\dfrac{1}{3}\right)^2=\dfrac{9}{4}\\ \Rightarrow\left[{}\begin{matrix}2x+\dfrac{1}{3}=\dfrac{3}{2}\\2x+\dfrac{1}{3}=-\dfrac{3}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{6}\\2x=-\dfrac{11}{6}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{12}\\x=-\dfrac{11}{12}\end{matrix}\right.\)