(2\(x\) - 3)2 : 3 = - 9:(2\(x\) - 3) (đk \(x\) ≠ \(\dfrac{3}{2}\))
⇒ (2\(x\) - 3)2.(2\(x\) - 3) = - 9.3
(2\(x\) - 3)3 = - 27
(2\(x\) - 3)3 = (-3)3
2\(x\) - 3 = - 3
2\(x\) = - 3 + 3
2\(x\) = 0
\(x\) = 0
Vậy \(x\) = 0
(2x-3)2 : 3 = -9 : (2x-3)
(2x-3)2.(2x-3) = -9.3
(2x-3)3 = -27 = (-3)3
=> 2x-3=-3
2x =-3+3=0
x = 0 : 2 = 0 => Vậy x = 0