(2x-1).(-1/3x+9)=0
\(\Rightarrow\) TH1: 2x-1 =0 \(\Rightarrow\) 2x=1\(\Rightarrow\) x= \(\frac{1}{2}\)
TH2: -1/3x+9=0 \(\Rightarrow\) -1/3x=-9 \(\Rightarrow\) x= 27
Vậy x= \(\frac{1}{2}\)hoặc x=27
Tìm x: (2x-1). (3x+9)=0
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Tìm số tự nhiên x thỏa mãn :
a) (2x+3).(5x-15)=0 b) (3x+1).(3x-9)=0
Bài 2: Tìm x thuộc Z sao cho:
a. (x + 1).(3 - x) = 0
b. (x - 2).(2x - 1) = 0
c. (3x + 9).(1 - 3x) =0
tìm X
1/4+2.(3.x-2/3)=1
(1/2+2X). (2x-3)=0
(4x-5).(5/4.x-2)=0
1/9-(2.x+1/2)mũ 2=0
9.(3x-1/2)mũ 2 =4
1/2.x+2/3.x-1=-10/3
X+1/12=-3/9
1.Tìm số nguyên x thỏa mãn
(-2+x).(3x-6)=0
(3x+9).(2x+6)=0
Tìm các số nguyên x, biết:
a) (x - 1) . (x + 2) = 0
b) (2x - 4) . (3x + 9) = 0
2. tìm x thuộc Z:
a. (x+1).(3-x)=0
b. (x-2).(2x-1)=0
c. (3x+9).(1-3x)=0
d. (x2+1).(81-x2)=0
Tìm x biết:
a) (2x + 3/5)^2 - 9/25 = 0
b) 3.(3x - 1/2)^3 +1/9 =0
