Sửa đề: \(\left(\frac12-\frac14\right):x=\frac12+\frac16+\cdots+\frac{1}{132}\)
Ta có: \(\left(\frac12-\frac14\right):x=\frac12+\frac16+\cdots+\frac{1}{132}\)
=>\(\frac14:x=1-\frac12+\frac12-\frac13+\cdots+\frac{1}{11}-\frac{1}{12}\)
=>\(\frac14:x=1-\frac{1}{12}=\frac{11}{12}\)
=>\(x=\frac14:\frac{11}{12}=\frac14\cdot\frac{12}{11}=\frac{3}{11}\)