\(y=\dfrac{\left(2x^2+x-6\right)+5}{x+2}=\dfrac{\left(x+2\right)\left(2x-3\right)+5}{x+2}=2x-3+\dfrac{5}{x+2}\)
\(\lim\limits_{x\rightarrow\infty}\left(y-\left(2x-3\right)\right)=\lim\limits_{x\rightarrow\infty}\left(-\dfrac{5}{x+2}\right)=0\)
\(\Rightarrow y=2x-3\) là tiệm cận xiên