\(x^2+8x-9\)
\(=x^2-x+9x-9\)
\(=x\left(x-1\right)+9\left(x-1\right)\)
\(=\left(x-1\right)\left(x+9\right)\)
Câu đầu chưa học sorry
( x3 - 3x2 + 3x -1 ) : ( x2 - 2x + 1)
= ( x -1 )3 : ( x - 1 ) 2
= x -1
x2 + 8x - 9
= x2 -x + 9x - 9
= x ( x - 1 ) + 9 ( x- 1)
= ( x -1 ) ( x + 9)