\(\dfrac{1}{4}+\dfrac{8}{9}< =\dfrac{x}{36}< 1-\left(\dfrac{3}{8}-\dfrac{5}{6}\right)\)
=>
=>\(\dfrac{31}{36}< =\dfrac{x}{36}< 1-\left(\dfrac{9}{24}-\dfrac{20}{24}\right)\)
=>\(\dfrac{31}{36}< =\dfrac{x}{36}< 1-\dfrac{-11}{24}=\dfrac{35}{24}=\dfrac{52,5}{36}\)
=>31<=x<52,5
mà x nguyên
nên \(x\in\left\{31;32;...;51;52\right\}\)