\(\frac{5x+2}{x-2}=-3\)
ĐKXĐ : x khác 2
=> 5x + 2 = -3( x - 2 )
<=> 5x + 3x = 6 - 2
<=> 8x = 4
<=> x = 1/2 ( tm )
Vậy S = { 1/2 }
Trả lời:
\(\frac{5x+2}{x-2}=-3\left(đkxđ:x\ne2\right)\)
\(\Leftrightarrow5x+2=-3\left(x-2\right)\)
\(\Leftrightarrow5x+2=-3x+6\)
\(\Leftrightarrow5x+3x=6-2\)
\(\Leftrightarrow8x=4\)
\(\Leftrightarrow x=\frac{1}{2}\left(tm\right)\)
Vậy \(S=\left\{\frac{1}{2}\right\}\)