Câu hỏi của KHÁNH CHI

Question

tìm số tự nhiên x sao cho x +2019/ x+ 2018= 4038/4037

Đoàn Trần Quỳnh Hương · Accepted Answer

(x+2019) x 4037=(x+2018) x 4038

⇒4037�+(4037×2019)=4038�+(4038×2018)⇒4037x+(4037×2019)=4038x+(4038×2018)

⇒4037�+8150703=4038�+8148684⇒4037x+8150703=4038x+8148684

⇒4037�−4038�=−8150703+8148684⇒4037x−4038x=−8150703+8148684

⇒−�=−2019

⇒�=2019⇒x=2019Câu trả lời: (x+2019) x 4037=(x+2018) x 4038

⇒4037�+(4037×2019)=4038�+(4038×2018)⇒4037x+(4037×2019)=4038x+(4038×2018)

⇒4037�+8150703=4038�+8148684⇒4037x+8150703=4038x+8148684

⇒4037�−4038�=−8150703+8148684⇒4037x−4038x=−8150703+8148684

⇒−�=−2019

⇒�=2019⇒x=2019

Trần Trung Đạt · Answer

x+2019) x 4037=(x+2018) x 4038

⇒4037�+(4037×2019)=4038�+(4038×2018)⇒4037x+(4037×2019)=4038x+(4038×2018)

⇒4037�+8150703=4038�+8148684⇒4037x+8150703=4038x+8148684

⇒4037�−4038�=−8150703+8148684⇒4037x−4038x=−8150703+8148684

⇒−�=−2019

⇒�=2019⇒x=2019

1 tick với nhaCâu trả lời: x+2019) x 4037=(x+2018) x 4038

⇒4037�+(4037×2019)=4038�+(4038×2018)⇒4037x+(4037×2019)=4038x+(4038×2018)

⇒4037�+8150703=4038�+8148684⇒4037x+8150703=4038x+8148684

⇒4037�−4038�=−8150703+8148684⇒4037x−4038x=−8150703+8148684

⇒−�=−2019

⇒�=2019⇒x=2019

1 tick với nha